[Retros] Messigny 2006 retro composing results

[CAILLAUDM at aol.com]

Hello,
Here it is.
Sorry for the great delay in posting this award.
Best,
 Michel
 
There were 12 entries by 7 composers.
I made 2 mistakes in the  announcement.
1) I forgot to mention than in the Pronkin spirit, the original  piece has to 
be captured; in consequence, I had to accept entries with the wrong  
"Messigny" definition, though they were underrated as less paradoxical than the  "real 
thing".
2) I didn't put a limitation on number of entries per composer;  Andrey 
Frolkin took the opportunity to enter 5 problems, all of them of a good  level as 
could be expected. One of the goals of these quick tourneys is to bring  
newcomers to the genre, and it would not be very encouraging if the awards were  
overwhelmed by "professionnals". So I applied an a posteriori limitation of 2  
problems per composer (also economizing my job on the place) and I will make it  
systematically for the next quick tourneys I will organize (Champagne...).  
 
Prize
Andrey  Frolkin
qNNkQ3/nrRPp3/Knrpp1p1/pBp5/P7/RP6/p1PP2P1/2B4b
13 last single  moves? (14+14)
the most profond conception on the theme where Pronkin appears  in the try 
and anti-Pronkin in the solution!
There are numerous tries of  unpromoting pieces on f8,g8, the most 
interesting, from a thematical point of  view, being the one where WBc1 is a Pronkin.
The reality is that WBc1 is in  fact an anti-Pronkin which performed a 
swichback, quite unexpected when  considering the diagram!
last moves :
-1.Qf7-é8+ h2-h1=B -2.Bb2-ç1 h3-h2  -3.Bg7-b2 h4-h3 -4.Bf8-g7 h5-h4 -5.Qg8-f7 
h6-h5 -6.g7-g8=Q h7-h6  -7.h6×Bg7
then Bf8 goes back to ç1!, b2-b3, R~-a3, a3-a2, b4×Ba3! (a black  colored 
Bishop is the only piece that can unpromote on f8!), b5-b4, f7-f8=B,  f6-f7, f7×Qé
6, é6×Bd7
Pronkin try : -5.Q~-f7 h6-h5 -6.f7-f8=B h7-h6 -7.f6-f7  f7×Q,R,Né6 but the 
original WQB can never go back home!
Other tries :  -2.b2-b3 b3×Na2 with Knight promoting on f8,g8 or screening on 
e8, all ending in  retrostalemate.
I find Bh1 ugly, and I don't think it justifies adding 2  (obvious) single 
moves to the retroplay, but that is a question of personal  taste.
 
1st HM
Dmitrij  Baibikov
8/2ppp3/1p4p1/BrPP4/RQRp4/3b1p1p/k2bPPP1/r1K1qB2
Add men   (11+14)
add WQd1,WNb1,BNa3
the 26 last moves are precisely  determined!
-1…Bç3-d2+ -2.Nd2-b1 Bb1-d3+ -3.Né4-d2 h4-h3 -4.Nf6-é4 h5-h4  -5.Ng8-f6 h6-h5 
-6.g7-g8=N h7-h6 -7.h6×Ng7 Nf5-g7 -8.h5-h6 Né3-f5 -9.Qd3-d1  Nd1-é3+ 
-10.Qf5-d3 f4-f3 -11.Qf8-f5 f5-f4 -12.Qa8-f8 f6-f5 -13.a7-a8=Q f7-f6  -14.a6-a7 
a7×Q,R,Nb6
Without the WQb3 on diagram, making Qd1 a "Messigny  Pronkin", this beautiful 
problem would have got a Prize.
Also I would have  prefer a presentation with Na3 on board. Given the theme 
it looks better if only  thematical pieces are "materialized" by the 
stipulation; the difficulty of  solving is not the more important criteria in this case. 
 
2nd HM ex aequo
Andrey Frolkin et Thierry Le Gleuher
Both composers  hit on the same idea with very near renderings (note the 
trick of WKc7 to  precise the last moves).
Also Gerd Wilts used a similar mechanism but without  the sucessful AUW.
 
Andrey
5b1N/ppK1pPkR/4ppr1/4p1PB/6p1/8/2p2P1P/RNBQ4
Where did the  promotions take place?  (12+11)
last moves :
-1.Rh6-h7+ ç3-ç2  -2.Qd8-d1 ç4-ç3 -3.d7-d8=Q ç5-ç4 -4.d6-d7 ç6-ç5 -5.ç5×Q,R,N
d7-d8=B, ç7-ç8=R,  ç7-ç8=N
 
Thierry
5bBN/ppK1pPkP/4pRrn/4ppP1/6p1/2p5/8/RNBQ4
Solve the position  (11+12)
last moves :
-1.Qd8-d1 ç4-ç3 -2.d7-d8=Q ç5-ç4 -3.d6-d7 ç6-ç5  -4.ç5×Q,R,N
d7-d8=B, ç7-ç8=R, ç7-ç8=N
 
The mechanism for getting 4 promotions is known from Alexandr Kislyak, for  
example
Alexandr Kislyak, Prize, Cherkaskaya Pravda  1990
5b1q/4prp1/4PPK1/5p1p/6kP/PPP1PR1b/4PrRn/5BB1
Solve the position  (13+11)
last moves :
-1.g3×Bh4+ Bg5-h4 -2.é5-é6 Bh6-g5 -3.f4×Qé5 Qé4-é5  -4.g5×Nf6 Qb1-é4 
-5.h4×Ng5 b2-b1=Q -6.a2-a3 a3×Nb2 then d1=N twice (Knights  uncaptured on f6,g5) and 
c1=B with final unlocking by d2×Né3
Kislyak has no  AUW but the promoted pieces are captured, that is much more 
difficult than  leaving them on the board! That is why the problems are HMs and 
not  Prizes.
 
1st Com
Gerd  Wilts
5bqn/1p2PrkN/3pprbN/5pRQ/6pB/6Pb/P1P1P2P/4KB1R
Solve the position  (14+13)
retro-play : a7-a8=R b3×Pa4, ç7-ç8=B d2×Pç3, g2×Bf1=B, h3×Rg2 then  :
-n.Rg1-g2 ç4-ç3 -n+1.g2-g3 ç5-ç4 -n+2.Bf2-h4 ç6-ç5 -n+3.Qh4-h5 ç7-ç6  
-n+4.Rh5-g5 a5-a4 -n+5.Ng5-h7 Kh7-g7 -n.6.N~-g5+
So, Bf1 and Rh1 are  Pronkin.
The promoted Bh3 is a flaw. (Amusing detail?! : placed at ç8 on the  diagram, 
it would be a "Messigny Pronkin")   
 
2nd Com
Philippe  Leroy
rnbqkbnr/ppppppp1/8/8/8/1P3P2/1PPPP1PP/1NBQK1N1
Solve the position  (13+15)
A very attractive position.
An original Knight had to capture "a  la anti-Pronkin", the WKB on f1, future 
promotion (to Knight) square.
An  original Knight was captured on b3.
Then black h Pawn could the 2 WR, promote  and replace the captured Knight, 
"a la Pronkin".
I think the problem could  support an extra stipulation "a la Smullyan" such 
as "BNb8 never moved" to have  more determination in the retroplay. 
 
3rd Com
Pascal  Wassong
2N3B1/p2ppp1P/6pr/6pN/6P1/1p1PPPRK/PP1pkrnn/2BR1bbq
Solve the  position (14+16)
Try :
-1.ç7-ç8=N b4-b3 -2.ç6-ç7 b5-b4 -3.ç5-ç6 b6-b5  -4.ç4-ç5 retro-stalemate
Solution :
-1.Nd6-ç8 b4-b3 -2.Nf5-d4 b5-b4  -3.Nh4-f5 b6-b5 -4.Nf6-h5 Rh5-h6 then Knight 
initially on f5 unpromotes on  c8.
Not really an Anti-Pronkin as the promoted Knight is on the diagram  

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