[Retros] eight officers homebase mate (new name for total homebase mate)-STATUS
raosorio at fibertel.com.ar
raosorio at fibertel.com.ar
Sun Nov 19 11:43:45 EST 2006
Hi,
Having in mind Andrew's comment,
"In contrast to Roberto, I would not object if one of these SPGs involved the capture
of homebase officers"
I've changed the task name for a more precise one: EIGHT OFFICERS HOMEBASE MATE.
This presents 11 task cases that are included in the general concept of homebase, where
some officers could be absent. After optimizing this, the general approach could be started.
I include here downstream the task definition, the cases and present status, wich includes
many inedit PGs from Lois/Osorio.
This task, combined with the economy on pawn captures, defines a challenging working
line. I'm sure that everybody will find that the here included PGs are not trivial or too easy to
solve. solutions are not included yet to make it funnier.
Nicolas will find here an answer to his request,
"It might be appealing to find a case where the 2 records are different.
I tried Kh3 with only Pd7 missed for black, without success"
EIGHT OFFICERS HOMEBASE MATE - CONCEPTUAL DEFINITION
CONSTRAINTS
PG diagram showing a mate position where the mating side has its 8 officers
at homesquare and the remaining pawns at homesquare too. Standard material
CASES
There are 11 different cases based on the checking piece and the checking line
( the mated king position is not relevant, just the checking line)
R(h) - mate by rook on (h) row
R(a) - mate by rook on (a) row
B(c) - mate by c1/c8 bishop
B(f) - mate by f1/f8 bishop
Q(lD) - mate by queen on its homesquare long diagonal
Q(sD) - mate by queen on its homesquare short diagonal
Q(d) - mate by queen on (d) row.
N(b)K(a)- mate by knight from its b1/b8 homesquare and oposite king on a3/a6
N(b)K(c)- mate by knight from its b1/b8 homesquare and oposite king on c3/c6
N(g)K(f)- mate by knight from its g1/g8 homesquare and oposite king on f3/f6
N(g)K(h)- mate by knight from its g1/g8 homesquare and oposite king on h3/h6
TASK DEFINITION
Defining,
p: homebase mating side missing pawns
m: PG single moves
c: other side missing pieces
a PG is characterized as (p,m,c). The task asks for economy, so p, m and c have
to be minimized. Two different orders define two different tasks,
1) Material task: minimize first p, then m and finally c.
2) Dynamic task : minimize m, then p and finally c.
PRESENT STATUS (nov 19th 2006)
In the vacancy of dynamic record the existing material one is considered to be the
double record.
MATERIAL TASK DYNAMIC TASK
************************************************************************
CASE (p,m,c) Author (p,m,c) Author
************************************************************************
R(h) - (1,14,?) Andrew Buchanan
------------------------------------------------------------------------
R(a) - (1,18,?) Andrew Buchanan
------------------------------------------------------------------------
B(c) - (1,28,6) R.Osorio & J.Lois (2,24,1) R.Osorio & J.Lois
------------------------------------------------------------------------
B(f) - (1,27,3) J.Lois & R.Osorio
------------------------------------------------------------------------
Q(lD) - (1,27,4) J.Lois & R.Osorio (2,18,4) Nicolas Dupont
------------------------------------------------------------------------
Q(sD) -
------------------------------------------------------------------------
Q(d) - (1,19,3) J.Lois & R.Osorio (2,17,2) R.Osorio & J.Lois
------------------------------------------------------------------------
N(b)K(a)- (1,24,4) R.Osorio & J.Lois
------------------------------------------------------------------------
N(b)K(c)- (2,25,3) J.Lois & R.Osorio
------------------------------------------------------------------------
N(g)K(f)- (3,27,5) R.Osorio & J.Lois
------------------------------------------------------------------------
N(g)K(h)- (1,24,4) J.Lois & R.Osorio
************************************************************************
The proof games
------------------------------------------------------------------------
R(h) (1,14,?) Andrew Buchanan
rnbqkbnr/ppppppp1/8/8/4P3/3B4/PPPPNPP1/RNB3RK
R(a) (1,18,?) Andrew Buchanan
rnbqkbnr/1ppppppp/8/8/3P1Q2/4B3/1PP1PPPP/KR3BNR
Q(d) (1,19,3) Jorge Lois & Roberto Osorio
rnb1q3/pppkrp2/2p1p2p/8/8/8/PPP1PPPP/RNBQKBNR
Q(d) (2,17,2) Roberto Osorio & Jorge Lois
rnb1qbn1/p1pkppp1/2p1p3/8/8/8/PP2PPPP/RNBQKBNR
Q(lD) (1,27,4) Jorge Lois & Roberto Osorio
1n4n1/2q1p3/2pr2pr/6bk/7p/8/PPPP1PPP/RNBQKBNR
Q(lD) (2,18,4) Nicolas Dupont
rnbqkbnr/ppp2ppp/8/4P2B/7K/6B1/PP4PP/RNBQKBNR
B(f) (1,27,3) Roberto Osorio & Jorge Lois
1n4n1/rpp3p1/kb3r2/p3p1q1/8/7b/PPPP1PPP/RNBQKBNR
B(c) (1,28,6) Jorge Lois & Roberto Osorio
rnbqkbnr/ppp1pppp/8/2P5/7P/6BK/P3P1PQ/5NN1
B(c) (2,24,1) Roberto Osorio & Jorge Lois
rsbqkbsr/ppp2ppp/2P5/8/8/3PP1BK/P2PS1PP/RS1Q1B1R
N(g)K(h) (1,24,4) Jorge Lois & Roberto Osorio
rnbqkbnr/ppppppRp/7K/6BP/8/4P3/PP3PP1/1N1Q2N1
N(g)K(f) (3,27,5) Roberto Osorio & Jorge Lois
3q1bs1/5p1p/5p2/3p4/4r1b1/5k2/PPP1sP1P/RSBQKBSR
N(b)K(a) (1,24,4) Roberto Osorio & Jorge Lois
rnbqkbnr/pRpppppp/K7/PB6/8/3P4/1PP3PP/1N1Q2N1
N(b)K(c) (2,25,3) Jorge Lois & Roberto Osorio
rn1q4/pppprpp1/8/8/1bn5/2k5/P1P1PPPP/RNBQKBNR
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