[Retros] The problemist, november 2007

[Joost de Heer]

And another one, in the comments of the fairy section:

F2532Rv - René J. Millour
4S1rR/2qs4/4p3/1p3Q1p/2p1pp2/b4k1p/K2s4/1b1R1r2 (5+15)
+---+---+---+---+---+---+---+---+

|   | . |   | . | S | . |*R | R |

+---+---+---+---+---+---+---+---+

| . |   |*Q |*S | . |   | . |   |

+---+---+---+---+---+---+---+---+

|   | . |   | . |*P | . |   | . |

+---+---+---+---+---+---+---+---+

| . |*P | . |   | . | Q | . |*P |

+---+---+---+---+---+---+---+---+

|   | . |*P | . |*P |*P |   | . |

+---+---+---+---+---+---+---+---+

|*B |   | . |   | . |*K | . |*P |

+---+---+---+---+---+---+---+---+

| K | . |   |*S |   | . |   | . |

+---+---+---+---+---+---+---+---+

| . |*B | . | R | . |*R | . |   |

+---+---+---+---+---+---+---+---+
h -2 & #1 (4 solutions), Mars Circe

Forward mate is every time 1. R(h1)xf1#
-1. Qg1(d8)xQc7 Qf8-f5 -2. g2-g1=Q f7-f8=Q
-1. Rg1-g8 Rf8-h8 -2. g2-g1=R f7-f8=R
-1. Bg1(f8)xBa3 Bf8-a3 -2. g2-g1=B f7-f8=B
-1. Sg1(b8)xSd7 Sf8-d7 -2. g2-g1=S f7-f8=S