[Retros] Die Schwalbe Heft 240 (Dec 2009)

[Joost de Heer]

Four retro articles in this issue, I'll give the originals:

Article 1: Günther Weeth: Neues zum Thema "Magisches Feld unter der 
Bedingung Anticirce" (news to the theme 'Magic square using the 
condition Anticirce')

This article is about what happens on a magic square in combination with 
anticirce, when a piece captures on the magic square. The author decides 
to use two types of magic squares:
Type I: No recolouring of the piece that captures, it's reborn on its 
normal square ('passthrough magic square')
Type II: The piece is recoloured and reborn according to its new colour.

Günther Weeth
Die Schwalbe Heft 240
q1B4k/pprP2bs/PPp2P1R/6P1/2P1p3/8/8/B3K3 (10+9)
-7 & s#1, Proca retractor, Anticirce Cheylan, magic square e6 (Type II)
-1. Kf8xSg8[Ke1] Qb8-a8 -2. Sd5xRe6[=bS; Sg8] zz e5-e4 -3. Re7-e6[=bR] 
e6-e5 -4. Rh1-h6 Bh6-g7 -5. Bc3-a1 Bg7-h6 -6. Be1-c3 Bh6-g7 -7. 
Rh7xPf7[Rh1] (previous black move was a capture on the f-file with a 
pawn) & 1. Re6[=b; Ra8] Qc8[Qd8]#

Article 2: Andrei Kornilov, Andrei Frolkin: Formale Bewertung von 
Retro-Elementen (oder: Kleine Hilfestellung für Retro-Preisrichter) 
(formal evaluation of retro-elements (or: a little bit of help for 
retro-judges)

Long article about the different values a judge should give to retro 
elements. Perhaps Andrei Frolkin can give a better synopsis of the 
article than I can. No new originals

Article 3: Siegfried Hornecker, Bernd Schwarzkopf: Der einzige Zug setzt 
matt/patt - Nachtrag (the only move gives mate/stalemate - addendum)

Kari Karhunen (KxR#)
8/8/8/6p1/5pPk/3p1P1p/3PpKpP/4Bbrb (6+10)

Bernd Schwarzkopf (RxP#)
5kBK/5PRP/5PpB/6P1/8/8/8/8 (8+2)

Kari Karhunen, Per Olin (SxQ#)
8/8/5p1p/5P1P/5PBR/2p2PPR/2p1pppS/2Kbrqrk (10+12)

Michael Schlosser (SxR#)
S1k5/1pPp4/brbP4/1p1p4/pP1P4/Kp6/1P6/8 (7+10)

Siegfried Hornecker, Per Olin (PxR#)
8/8/6pp/6pk/5prp/5PpK/6P1/8

Bernd Schwarzkopf, Harald Grubert (PxS=X#)
5sKB/3p2Ps/3Ppkp1/4p1p1/4P1P1/8/8/8 (6+8)

Kari Karhunen (PxPep#)
S1b1brbr/1pPp1k1s/bP1P1p1P/Bp1P1PpK/1P4P1/8/8/8 (11+13)

Silvio Baier, Bernd Schwarzkopf, Michael Schlosser, Per Olin (KxR=)
6k1/5pPp/5Pbr/5pKp/5P1P/8/8/8 (5+7)

Michael Schlosser (RxS=)
8/8/8/8/8/5p1p/1pp1pP1P/brk1K1sR (4+9)

Silvio Baier (L-=)
8/8/8/8/5p1p/5P1k/5P2/6BK (4+3)

Bernd Schwarzkopf, Mario Richter (BxR=)
5bBk/4pPpr/4p1Kp/4P2P/8/8/8/8 (5+7)

Bernd Schwarzkopf, Michael Schlosser (BxS=)
2k5/s1Pp4/PBpP4/KpP5/1P6/8/8/8 (7+5)

Per Olin, Mario Richter (SxQ=)
1S1k4/ps1P1p2/qpKp1P2/bpbP4/1p1p4/1P1P4/8/8 (7+12)

Bernd Schwarzkopf, Per Olin (SxR=)
5b1S/4pPp1/3pPkrp/3P2pK/3P2P1/8/8/8 (7+8)

Bernd Schwarzkopf, Per Olin, Mario Richter (SxB=)
1S1k4/1s1P1p2/bpKp1P2/bpbP4/1p1p4/1P1P4/8/8 (7+11)

Siegfried Hornecker, Per Olin (SxP=)
8/8/8/8/1p2p3/pPk1P3/P1p1P3/S1K5 (6+5)

Michael Schlosser, Bernd Schwarzkopf, Per Olin (PxR=)
8/8/8/1p6/brp5/Pbp5/p1p5/k1K5 (2+9)

Bernd Schwarzkopf (PxS=)
6k1/5pPp/5Pbs/5pPp/5PpK/6P1/8/8 (6+8)

Bernd Schwarzkopf (PxS=X=)
4k1Ss/3pPpPP/3P1PpK/6P1/8/8/8/8 (8+5)

Article 4: Silvio Baier - Neue ökonomische Pronkins (new economical 
Pronkins)

An update on Silvio's article from Die Schwalbe 232.

Silvio Baier
1r6/1p2k1pp/s3pp2/s1p5/1q4b1/1pb1PB2/1PPrpPPP/RSBQK1SR (14+16)
SPG 23.5
[The printed diagram is missing bPe2!]
1. e3 d5 2. Be2 d4 3. Bf3 d3 4. Ne2 dxe2 5. d4 a5 6. Nd2 a4 7. Nb3 axb3 
8. a4 Bg4 9. a5 e6 10. a6 Ne7 11. a7 Na6 12. d5 Rb8 13. a8=N Nc6 14. Nb6 
Na5 15. Na4 Bb4+ 16. Nc3 c5 17. d6 Qb6 18. d7+ Ke7 19. d8=N f6 20. Nf7 
Rhd8 21. Ng5 Rd2 22. Nb1 Bc3 23. Nh3 Qb4 24. Ng1

Silvio Baier
rsbqk1sr/1pp1bpp1/4PR2/4p3/4P1p1/1P1RKB2/1PP2PP1/1SBQ2S1 (15+14)
SPG 22.0
1. e4 h5 2. Qg4 hxg4 3. d4 Rh3 4. d5 Rb3 5. axb3 e5 6. Ra6 Be7 7. Rf6 a5 
8. h4 Ra6 9. h5 Re6 10. dxe6 d5 11. h6 d4 12. h7 d3 13. h8=Q d2+ 14. Ke2 
d1=R 15. Qh6 Rd3 16. Qd2 Rh3 17. Qd1 Rh8 18. Rh3 a4 19. Rd3 a3 20. Ke3 
a2 21. Be2 a1=R 22. Bf3 Ra8

ORIGINALS HEFT 240

14314 - Nikolai Beluchov
SbB5/QRRp2pp/Spp1p2P/k7/p1P2p2/K2P4/qPrP2P1/r1Bs4 (14+14)
Release the position!

14315 - Joaquim Crusats, Andrei Frolkin
3bk1sr/2Rp3p/SpBp3p/B4K2/5P2/PP4pP/2R2p1P/8 (11+11)
-17 & #1, Proca retractor

14316 - Stephan Dietrich
2k3sr/p1p1pp1p/bs4p1/3p4/8/8/PPSPPPPP/RS2KBSR (14+12)
SPG 11.5

14317 - Bernd Gräfrath
b3k1sr/p2ppp1p/2s3p1/2p5/8/8/P2PPPPP/b1BQKBSR (12+13)
SPG 9.0, Losing chess
[Bernd already mailed the printing error: Sd1->Qd1]

14318 - Paul Raican, Vlaicu Crisan, Ion Murarasu
2bq3r/pp5p/4S2k/2ppppp1/PPPPPPPP/8/8/RSBQK2R (15+12)
SPG 34.0, Duellist

14319 - Paul Raican
2k2b1r/8/6b1/2P3P1/r1P1P3/p7/3K4/3B4 (6+6)
-8 & #1, Proca retractor, Circe assassin

14320 - Günther Weeth, Klaus Wenda
7s/bsp2r2/r2p4/k1q5/8/1bp5/6p1/4K3 (1+12)
-7 & #1, Proca retractor, Anticirce, Magic square f2

14321 - Per Grevlund
8/1p4pp/8/3p4/8/3R1P1p/1K2P3/8 (4+5)
Add two black pieces for #1, Monochrome chess
b) d5->e5

14322 - Andreas Thoma
RSBQKBSR/8/8/8/1q6/8/8/1k6 (8+2)
After 5 moves all white pieces are on their homesquare
Circe, anticirce

14323 - Bernd Schwarzkopf
Illegal cluster with wK, 3wB, bK (4+1). The white king is on a white 
square, the white bishops on an edge square.
[IC mit wK, 3wL, sK (4+1). Der weiße König steht auf einem weißen Feld, 
die weißen Läufer auf Randfeldern]

14324 - Bernd Schwarzkopf
Illegal cluster with wK, wR, wB, wS, bK (4+1). In the IC, the black king 
is mate, and the distance between the homesquare and the actual square 
for both kings is equal.
[IC mit wK, wT, wL, wS, sK (4+1). Die gesuchte Stellung ist eine 
Mattstellung, in der die Entfernungen der beiden Könige zu ihren 
jeweiligen Ursprungsfeldern gleich sind.]

SOLUTIONS HEFT 237
------------------
*14123 - Heinonen
1. Nf3 b5 2. Nd4 Bb7 3. Nxb5 Bxg2 4. Nxa7 c6 5. Nxc6 Ra3 6. h3 Rxh3 7. 
Rxh3 Bxh3 8. Nxb8 Bxf1 9. Kxf1 Qxb8 10. Ke1 Qd8
Cook: 1. Nf3 c6 2. Ne5 Qc7 3. Nxc6 Qxh2 4. Nxa7 Qxg2 5. Rh2 Qxh2 6. Bg2 
Qc7 7. Bxb7 Nc6 8. Bxc8 Rxc8 9. Nxc6 Rd8 10. Nxd8 Qxd8

*14124 - Gasperjan
[Printing error: bPe7 missing]
1. f4 Nh6 2. f5 Rg8 3. f6 gxf6 4. Kf2 Rg3 5. Qe1 Rd3 6. exd3 Na6 7. Qe6 
dxe6 8. g4 Kd7 9. g5 Kd6 10. g6 Ke5 11. g7 Qd6 12. g8=Q Bd7 13. Qg2 Bg7 
14. Qxb7 Rh8 15. Bh3 Be8 16. Bf5 Kxf5 17. Nh3 Kg6 18. Rf1 Nf5 19. Kg1 h6
Cook: 1. g4 Na6 2. Bg2 Rb8 3. Bxb7 Nh6 4. Bd5 Rb3 5. Be6 Rd3 6. exd3 
dxe6 7. f4 Qd6 8. f5 Bd7 9. f6 gxf6 10. g5 Nf5 11. Nh3 Bg7 12. O-O O-O 
13. Qf3 h6 14. Qb7 Kh7 15. g6+ Kxg6 16. Kh1 Rh8 17. Kg1 Be8

14125 - Gräfrath
1. b3 b5 2. Bb2 b4 3. a4 ba3 4. Qc1 ab2 5. Kd1 ba1=Q 6. Qa3 d5 7. Kc1 
Kd7 8. Kb2 Kd6 9. Ka1
Queen Schnoebelen

*14126 - Grudzinski
1. f4 g5 2. fg5=S b5 3. Sh7=B b4 4. Bg8=R b3 5. Rg7=B ba2=S 6. Bc3=S 
Sc1=B 7. Ra7=Q Bb2=R 8. Qa8 Rb5=B 9. Qa1=R Bc6=S 10. Sa2=P Sa7=P
Cook: 1. f4 g5 2. fg5=S a5 3. b3 a4 4. Sh7=B ab3=S 5. Ba3=S Ra6=B 6. 
Bg8=R Bb5=S 7. Sb5=B Sa1=B 8. Bc6=S bc6=S 9. Rg7=B Sa7=P 10. Ba1=R

14127 - Millour
Without Rd1: -1. f6-f7 and 1. a8=Q#. So how to get rid of the rook?

In Mars-Circe, if two pawns of opposite colour are 'past each other' on 
the same file, at least one of the two must be on the second (black) or 
seventh (white) row, otherwise the pawns couldn't have gotten past each 
other (sequence is: wP->7th row, black captures on the 6th row, or black 
pawn to second row, white captures on third)
-1. b7-b8=R a2-a1=S -2. Kd5-c6 f2-f1=Q -3. Ke6-d5 b2-b1=B -4. Kf6-e6 
h2-h1=S -5. Kg7-f6 g2-g1=B -6. Kg8-g7 d2-d1=R -7. a6-a7 (a3-a2, f3-f2 
and h3-h2 are now illegal retractions, see text above) d3-d2 -8. f6-f7 & 
1. b8=Q#

14128 - Blacker
ELM: RxS

14129 - Keym
a) wKb8, wBa2; bKb1, bBa7 (distance of the kings is sqrt(58), distance 
of bishops is sqrt(26).
b) wKa8, wQa2, wQh1; bKa1 (distance of the kings is sqrt(65), distance 
of the queens is 6 (Qa2<-->a8)+4 (Qh1<-->d1), not 7 (Qh1<-->h8)+sqrt(10) 
(Qa2<-->d1).