[Retros] N2A: 18 down to 14

Noam Elkies elkies at math.harvard.edu
Mon Mar 14 17:28:48 EDT 2011


I wrote:

" I was actually hoping for an 8Q+0 or if necessary 9Q+0 position
" where *both* Kings' positions are uniquely determined.

While we don't have that, here's a 14-man realization of N2A:

Q4/R7/8/R7/4Q3/5n2/1PPPPPP1/2BN1B2

. . . Q . . . .
R . . . . . . .
. . . . . . . .
R . . . . . . .
. . . . Q . . .
. . . . . n . .
. P P P P P P .
. . B N . B . .

NDE



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